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trends in the physical properties of the elements accross a period and down a group(atomic radii boiling/melting point.ionisation of energies,types of struture)
trends in the chemical properties of the elements(metal/non metal,reactivity&reaction wih water
trends in the chemical properties of some compounds of the elements (reactivity and reations of the oxides with water

2007-02-23 22:22:38 · 4 answers · asked by Dany H 1 in Science & Mathematics Chemistry

4 answers

Atoms in each group (vertical column) on the periodic table has the same number of valence electrons. This means that atoms in the same group have similar chemical properties. However, as you move down the group each atom has more levels of inner core electrons than the one above it. These inner electrons act as a shield between the valence electrons and the nucleus. The valence electrons don't feel the attraction of the nucleus as strongly and are easily removed. That is why the electronegativity and ionization energy decrease as you go down the group.

As you go across a series or period on the table there are the same number of electron levels, but there are more protons in the nucleus and more valence electrons from one atom to the next. This is why the size of the atoms decreases as you move across the period and why the electronegativity increases from left to right across a period.

2007-02-23 23:10:53 · answer #1 · answered by physandchemteach 7 · 0 0

The placement on the periodic table does not affect properties of a substance. We don't find substances on the periodic table....we find elements. Elements are placed in the periodic table on groups of elements with the same properties: metals, nonmetals and metaloids. Another criteria is the number of valence electrons of each element.

2016-05-24 05:13:25 · answer #2 · answered by Anonymous · 0 0

dont you have a data book i do chemistry at school and thats how i would find out

2007-02-23 22:31:53 · answer #3 · answered by Anonymous · 0 1

its long answer...

2007-02-23 22:26:38 · answer #4 · answered by Anonymous · 0 1

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