Can you help me a problem in arrays of strings in C?

Question

How can I copy a string (array of character) to an array of string such as:

char text[a][b];

wherein a is the index number of the array and b is the max length of array of characters that can be stored in the array..

For example I have an array of characters "char word[20];"
How can I store it to an array of strings "char text[99][20];"??

Please help.. And thanks..

Answer 1

you can use the strcpy() function.

strcpy(text[99], word);

or:
for (int a = 0; a < 20; a++)
{
text[99][a] = word[a];
}

both will work.

Answer 2

for (int x=0; x<20; x++)
{
text[0][x] = word[x];
}

// This will copy the char array word into the first row in text.
// word is a one dimensional array.
// text is a two dimensional one.

Answer 3

it is C-String issue , As each and every physique suggested , you won't be in a position to resize c-strings, yet could nicely be solved making use of as : char *FirstName = char[20]; // could be-> char FirstName[20]; std::cin.getline(FirstName,20); int length = strlen(FirstName); //strlen seems for '0' for end of string char*editFirstName = new char[length+a million]; strcpy(editFirstName, FirstName); i could advise you to apply C++ Strings , i.e std::string. you're able to do some thing like : std::string FirstName; std::getline(FirstName,'n'); // no could resize FirstName now and quite person-friendly to apply. you're accomplished)

Answer 4

Yes it is possible!!
Wat U need to do is that for example
let


char word[5]={'a','b','c','d','e'};
char test[20][10];
for(i=0;i<5;i++)
{ {test[p][q]=word[i];
q++;}
if(q==10)p++;
}


Ok Gud LC Bye