2007-02-23 19:49:31 · 7 answers · asked by suhasnisingh 2 in Science & Mathematics ➔ Physics
W=(E^2)/R
Watts = 6^2/12
Watts = 36/12 = 3.
To derive that power formula from ohms law:
E=I*R so I=E/R
W=E*I; substitute for I to get W=(E^2)/R
2007-02-23 19:55:10 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋
P=U.I
and I=U/R
so P=U²/R
so P=36/12
P=3 Watt
2007-02-23 22:01:33 · answer #2 · answered by Anonymous · 0⤊ 0⤋
You will need ohm's law to calculate that answer.
I = E/R and P= EI
1. You know that E is 6V and R is 12 Ω.
2.. First, calculate I (Current)
3. Then you can calculate P (Power) from E * I
Good luck
2007-02-23 20:01:26 · answer #3 · answered by templeblot 3 · 0⤊ 0⤋
haha.
Same course as me, how much dissipation will be afflicted on a 12 core wire when you put 10 volts through it?
Who gives a ****!!
btw, i=v/r so 6 divided by 12 equals your answer.
but, who gives a ****
2007-02-23 19:54:48 · answer #4 · answered by Captain S 1 · 0⤊ 0⤋
3 watts
2007-02-23 19:54:46 · answer #5 · answered by DT 3 · 0⤊ 0⤋
power=work done/time taken
power= vit/t
power=vi
since you have been given resistance and voltage,
remember i=v/r
so now
power=(v*v)/r
power=(6*6)/12
power=36/12
power=3 watts
2007-02-23 21:10:39 · answer #6 · answered by PriYanKaPujA 1 · 0⤊ 0⤋
0.5 amperes
2007-02-23 20:01:03 · answer #7 · answered by Sai 1 · 0⤊ 0⤋