A swimming pool has a rectangular base 14ft long and 28ft wide. The sides are 6ft high, and the pool is half full of water. How much work will it take to empty the pool by pummping the water out over the top of the pool?. Assume that the water weighs 62.4lb/ft^3. How many ft lb's of work will it take to empty the pool?
2007-02-23 19:16:33 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
try the units trick;
volume of water = 14ft * 28ft * 3ft (half full) = 1167ft^3
find the weight of water;
w = 62.4lb/ft^3 * 1167ft^3 = 73382.4lb
now you can get the work in lb.m;
work = 73382.4lb * 3m = 220147.2lb.m
now i"ll leave you to convert the answer
2007-02-23 23:51:31 · answer #1 · answered by think_more 1 · 0⤊ 0⤋
Germs are inevitable in swimming pool. Germs can get into pool via many potential. Human physique is the main source. I won't say stay away from public swimming pools, yet ensure you get a solid bathe after swim. in case you have a private pool then you definitely could use Chlorine to get rid of germs besides as different issues like green algae.
2016-12-17 17:42:21 · answer #2 · answered by ? 4 · 0⤊ 0⤋
You find the change in potential energy in raising the water from the center of the pool to the top. mgh
2007-02-23 19:22:38 · answer #3 · answered by briankflau 2 · 0⤊ 0⤋
thinking in metric units solve half of the problem
the other half i leave to you
2007-02-23 19:21:32 · answer #4 · answered by gjmb1960 7 · 0⤊ 0⤋