write a c++ program that calculates minimum, maximum mean average of a given number?

Answer 1

of n numbers I suppose ....

tick tick tick

voila finished i just did it

Answer 2

Don't you mean given set of numbers?

Answer 3

enter validation is an considerable portion of this task, so earnings from it. The technique for show and summing of digits is comparable, so as that they could be blended. using separate applications, despite the fact that, makes them extra reusable - you will possibly be able to discover a desire for those in destiny classes. this ought to provide you some techniques for a thank you to jot down your application: #comprise iostream #comprise string #comprise sstream #comprise typeinfo   using namespace std;   template void getInput(T *in, bool (*)(T&)); bool isPositiveInt(int&); void explodeReverse(unsigned); unsigned sumDigits(unsigned); int considerable(int argc, char *argv[]) {     int n;     on a similar time as (actual) {         cout << "enter a favorable integer: " << endl;         getInput(&n, isPositiveInt);         explodeReverse(n);         cout << "sum to " << sumDigits(n) << endl << endl;     }     return 0; } unsigned sumDigits(unsigned n) {     if (n < 10) return n;     return (n % 10) + sumDigits(n / 10); } void explodeReverse(unsigned n) {     cout << n % 10 << " ";     if (n > 9) explodeReverse(n / 10); } bool isPositiveInt(int &i) {     return i > 0; } template void getInput(T *in, bool (*valid)(T&)) {     stringstream ss;     string line;     bool inputOk = fake;       cout << "> ";     do {         getline(cin,line);         ss.sparkling(); ss.str(line);         if (inputOk = (ss >> *in)) {             if (typeid(*in) == typeid(char)) {                 ss.forget approximately approximately();             }             inputOk = valid(*in) && !ss.reliable();         }         if (!inputOk) {             cout << "invalid enter, try lower back" << endl << "> ";         }     } on a similar time as (inputOk == fake); } #if 0 pattern run: enter a favorable integer: > -a million invalid enter, try lower back > invalid enter, try lower back > x invalid enter, try lower back > 19683 3 8 6 9 a million sum to 27 #endif

Answer 4

#include

using namespace std;

int main()
{
cout << "Enter your number" << endl;
int number;
cin >> number;
cout << " Minimum = " << number << endl << "Maximum = " << number << endl << "Mean average = " << number << endl;
system("pause");
return 0;
}

Answer 5

If you can't do this on your own, you should really consider choosing a different course/major.

Answer 6

is that a question,... a demand...or your homework?