2007-02-23 16:55:08 · 10 answers · asked by Ann 1 in Science & Mathematics ➔ Mathematics
√-3
= √[(3)(-1)]
= i√3
2007-02-23 16:58:51 · answer #1 · answered by sahsjing 7 · 0⤊ 0⤋
Square root of a negative number:
In the instance of real numbers (denoted by a capital R), there are no numbers that can be multiplied by itself with the result of a negative number.
In the instance of complex numbers (denoted by a capital C) you can find the square root of a negative number by multiplying by the imaginary unit i, where i^2 = -1 (i squared equals negative one)
â-3 = â3i
hope this helps!
2007-02-23 17:01:15 · answer #2 · answered by Anthony A 3 · 0⤊ 0⤋
square root of anegative number is imaginary or it is expressed in the form of a complex number
i^2= -1.
i =sqrt-1
-3 i*sqrt3
2007-02-23 17:17:09 · answer #3 · answered by RAJA 1 · 0⤊ 0⤋
you cant take the square root of a negitive number its just a law. but when you take a square root of a negitive you have to remember to add a (i) in front of it. (i) stands from imaginary because that number doesnt really exist.
2007-02-23 17:05:22 · answer #4 · answered by a.n. 1 · 0⤊ 0⤋
u can't have square root of the number with negative sign...that's y u've use i ...
so square root of -3 is itimes square root of 3
2007-02-23 17:05:47 · answer #5 · answered by Miss Question Mark 2 · 0⤊ 0⤋
the square root of -3=rad -3
so rad -3=i rad 3
i=rad -1 if you didnt know
so it would just be i rad 3
2007-02-23 17:07:56 · answer #6 · answered by pochacco90630 1 · 0⤊ 0⤋
you have to express the answer in imaginary (i)
i=sqrt of -1
so sqrt of -3 is sqrt of 3* sqrt of -1 right?
so that would be sqrt3i
2007-02-23 16:58:41 · answer #7 · answered by dave 2 · 0⤊ 1⤋
(3)*1/2i
2007-02-23 17:00:46 · answer #8 · answered by xyz 2 · 0⤊ 1⤋
there is no question like this
2007-02-23 17:00:30 · answer #9 · answered by Anonymous · 0⤊ 1⤋
i*sqrt3
2007-02-23 16:59:12 · answer #10 · answered by Al3xa 2 · 0⤊ 0⤋