The length of a rectangle is 10 in. more than twice its width. If the perimeter of the rectangle is 56 in., find the width of the rectangle.
ANSWERS:
5in.
6in.
7in.
8in.
2007-02-23 16:06:46 · 9 answers · asked by nazerbean1 1 in Science & Mathematics ➔ Mathematics
This problem can be solved with basic algebra:
Let width be represented by X
Length = 2x+10
Perimeter = 2*Width +2*Length
= 2(x) + 2(2x+10)
56 = 2x + 4x +20
56-20=6x
36=6x
x=6
Width = 6 in
2007-02-23 16:30:57 · answer #1 · answered by snowcat16 2 · 0⤊ 0⤋
Hey, don't panic!!!!!!!!
Here's your answer:
Consider the length to be "l", and width to be "w".
From the first line, I get: that the length (l) is ten times more than twice its width (w).
Forming the equation: l = 10 + 2w .................... (Equation A)
It is known that perimeter (p) is the sum of twice the length and width.
Therefore: p = 2 (l+w)
p = 2l + 2w ................................ (Equation B)
So, solving the two equations:
That is substituting the value of (l) from equation (A) in equation (B):
l = 10 + 2w
2 (10 + 2w) + 2w = 56
20 + 6w = 56
6w = 36
w = 6
So the width is 6 inches.
Just in case you want to find out the exact length, then you must substitute the value of (w) in either of the equations.
2007-02-23 16:26:14 · answer #2 · answered by artim 3 · 0⤊ 0⤋
we can write algebra equations that say the same thing as the word sentences in the problem
l=length of rectangle
w=width of rectangle
L=2w+10 (length of rectangle is 10 more than twice width)
2L+2w=56 (perimiter of rectangle is 56)
with the two equations and two unknowns you can solve several ways, substitution is probably most straight forward
since the first equation tells you what L equals, put that same expression for L, in for L in the other equation:
2(2w+10) + 2w = 56
now we just solve for "w"
4w+20+2w=56
6w=36
w=6
remembering that L=2w+10
L=2(6)+10
L=22
lets check it
2*22+2*6=56
44+12=56
56=56
voila
2007-02-23 16:15:05 · answer #3 · answered by enginerd 6 · 0⤊ 0⤋
Width=W
Length=2W+10
2(2W+10)+2W=56
Divide through by 2
(2W+10)+W=28
3W+10=28
3W=18
W=6in
2007-02-23 16:12:39 · answer #4 · answered by gumtrees 3 · 2⤊ 0⤋
ans is 6
w = a
l = 2a +10
perimeter = 2(2a +10 + a) = 56
=6
good luck!
2007-02-23 16:15:43 · answer #5 · answered by veddyq 2 · 0⤊ 0⤋
take 10 times 2. 56-20=36 36divided by 2 =18 none of them are right
2007-02-23 16:13:13 · answer #6 · answered by wildkat_110 1 · 0⤊ 3⤋
L = 2w + 10
2L + 2w = 56
L - 2w = 10
2L + 2w = 56
-----------------
L + 2L = 66
3L = 66
L = 66:3
L = 22
L - 2w = 10
22 - 2w = 10
-2w = 10 - 22
w = -12/-2
w = 6
Answer: w = 6in
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2007-02-23 19:03:49 · answer #7 · answered by aeiou 7 · 0⤊ 0⤋
6in
2007-02-23 16:14:34 · answer #8 · answered by JAMES 4 · 0⤊ 0⤋
5in
and wat grade are you in?
2007-02-23 16:27:44 · answer #9 · answered by tissysbaby 1 · 0⤊ 1⤋