Rewrite the equation... please help?

Question

2x – 3y = –6 as a function of x
a) f(x)=2/3x+2
b) f(x)=3/2x-3
c) f(x)=3/2x-6
d) f(x)=2/3x+6

Answer 1

2x – 3y = –6

subtract 2x
-3y = -2x - 6

divide -3
y = 2/3x + 2

A

Answer 2

f(x) is the same as y

(2x - 3y)/3 = -6/3 ... divided both sides by 3

2x/3 - y = -2 ... performed the division

-y = -2 - 2x/3 ... subtracted 2x/3 from both sides

y = 2 + 2x/3 ... multiplied both sides times -1

2 + 2x/3 = 2x/3 + 2 = (2/3)x = 2

So I say A

(but note that 2/3x + 2 is an incorrect way to write (2/3)x + 2)

Answer 3

2x - 3y = -6

So,move the 2x to behind the equal sign, the positive sign of 2x is changed to be negative, that's :
-3y = -2x - 6

Then, multiply it all with negative, so that there'll no be any negative number :
3y = 2x + 6

Divide all by 3:
3y/3 = y
2x/3 = 2/3x
6/3 = 2

so:
y = 2/3x + 2

(A) is the answer

Answer 4

A.

2x-3y=-6
-2x -2x (subtract 2x from both sides)

-3y=-6-2x
(-1)-3y=-6-2x(-1) (multiply both sides by -1)

3y=6+2x
3y/3=6/3+2x/3 (divide all terms by 3)

y=2+2/3x
f(x)=2/3x+2 <----answer.

Answer 5

I'm showing the steps:
2x-3y=-6
2x=3y-6 <-divide all that by 2
x=3/2y-3 is your final answer

Answer 6

2x = - 6 + 3y

3y = 2x + 6

y = (2/3).x + 2-----------ANSWER a)

Answer 7

Wow. That's some problem you got there.

I would cheat off of someone or just not figure it out.

Answer 8

a)

Answer 9

a)