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3 answers

any 6 consecutive integers contains a factor of 5, because a factor of 5 shows up every 5 integers. Also, since every other integer is even, there's obviously a factor of 2 in every consecutive 6 integers. 2*5 * blahblahblah... = 10*blahblahblah, so no matter which 6 consecutive integers you choose, the factor of 2 and 5 mean the last digit must be a 0.

2007-02-23 15:31:41 · answer #1 · answered by need help! 3 · 4 0

0

any 6 consecutive integers will have at least 1 with 5 as a factor & several with 2 as a factor. Any integer with 2 & 5 as factors will end in zero.

2007-02-23 15:54:36 · answer #2 · answered by yupchagee 7 · 0 0

Ha, the above guys are right, it's zero. My first thought was, any such product in the units place will multiply a 4 x 5, or else a 5 x 6 ... both of which give you a 0 in the units spot. And once you're at zero in the units place, you're stuck with it baby.

2007-02-23 16:06:33 · answer #3 · answered by KevinStud99 6 · 0 0

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