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What is the total number of orbitals in the principal quantum level n = 5 of an atom?

for exam review...plz help

2007-02-23 13:53:26 · 3 answers · asked by adam s 1 in Science & Mathematics Chemistry

3 answers

you use the formula 2nsquared to find the answer..so:
2n^2
2(5)^2
2(25)
50

2007-02-23 14:00:54 · answer #1 · answered by couturechic16 1 · 0 1

n =6 6s2 and 5f14 Makes a maximum of 16 electrons n =6 6s2 and 5f14, but only one ml is shown there the max. 3+ n =5 5s2 and ml = 1+ total = 3 as only one ml is shown. These can be used in any order, but only once each, the same is true for ms factor, as long as all the spins end up with own number. I guess these have to have the same spins until all the orbitals are half filled

2016-05-24 04:22:19 · answer #2 · answered by Anonymous · 0 0

the 2n^2 formula above gives the number of ELECTRONS that have a principal quantum number of n = 5

the number of orbitals in any energy level (any "n" value) is n^2
so for n = 5, the number of ORBITALS is 5^2 = 25 orbitals

another way to get this is to realize that there are 5 sublevels in the 5th energy level

s sublevel has 1 orbital
p sublevel has 3 orbitals
d sublevel has 5 orbitals
f sublevel has 7 orbitals
g sublevel has 9 orbitals
------------------------------------------
25 orbitals total

2007-02-23 14:32:47 · answer #3 · answered by chem geek 4 · 1 0

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