Two coins are tossed together 40 times. Approximately how many times should both land tails up?

Question

a)10
b)20
c)25
d)30

Answer 1

You want the probability that both are tails at the same time. Looking at the possible outcomes:
Tails and Tails
Tails and Heads
Heads and Tails
Heads and Heads

Getting both Tails is 1 out of 4 or 1/4. Therefore in 40 tosses you still wil get 1/4 which would imply.
40 * 1/40 = 10.

I say A) 10.

Answer 2

It's a. Lost and scattered and n0tsan3, you have no idea what you're talking about.

First, how many possibilities are there?
Possibility 1: Coin A = Heads, Coin B = Heads
Possibility 2: Coin A = Heads, Coin B = Tails
Possibility 3: Coin A = Tails, Coin B = Heads
Possibility 4: Coin A = Tails, Coin B = Tails

Each possibility has an equal chance of occuring; therefore the probability of both landing tails up (#4) is 1/4. Since there are 40 trials, you multiply 40 by 1/4 and get 10, choice a.

Answer 3

The fallacy is the word "should" when in fact no two instances would turn out exactly the same. The odds are based on chance and so simple logic applies. The chances are 50/50 that they "could" both land tails up. However, the square of opposition would present another option, therefore the answer is "e" all of the above.

Answer 4

It would be A because of the 50/50 chance. Always remeber when a problem like that comes up and it involves any coin, all you have to do is divide the number of times it's thrown by two. Because a penny, nickel, dime, etc. has only two sides. Unless, they invented new coins yesterday.... I this case though, there's 2 coins being thrown up 40 times so divide 40 by 4 and tada!!! You get A!

Answer 5

whilst a coin is tossed 40 circumstances, the possibility is one million/2 considering there are 2 sides of the coin and one component is tails. your opportunities are H or T so, 40 x one million/2 = 20 once you're tossing 2 money, you're doubling your opportunities that are HH, HT, TT and TH considering merely between the 4 is TT, you're possibility of having it to land the two tails is one million/4 so, 40 x one million/4 =10

Answer 6

If you toss two coins together, there are four possible ways they can land:

Heads + Heads
Heads + Tails
Tails + Heads
Tails + Tails

So, they will, on average, both land tails-up 25% of the time.

If you toss them 40 times, then they both should land tails-up 10 times.

Answer 7

A, 10. I think other people answering this question misread it. But if the coin is a penny the head side weighs more and tail will come up more often. Throw that in there and the teacher will be inpressed.

Answer 8

There is a 25% chance of two heads up. The answer is a)10

Answer 9

a)10

Answer 10

B there's a 50/50 chance because there are two sides (theoretical probability)