please help, 8th grade math!!!
2007-02-23 13:40:46 · 10 answers · asked by Brittney M 1 in Science & Mathematics ➔ Mathematics
P = 2(W+L)
the length are givens, just plug them in
70 = 2(W + 1)
35 = W + 1
W = 34ft
do the same thing for the other lengths
2007-02-23 13:46:14 · answer #1 · answered by 7 · 1⤊ 0⤋
1*2=2 70-2=68/2=34
If the length is 1 ft, the width will be 34 ft.
2*2=4 70-4=66/2=33
If the length is 2 ft, the width will be 33 ft
2*3=6 70-6=64/2=32
If the length is 3 ft, the width will be 32 ft
~Love swimmer
2007-02-23 21:47:35 · answer #2 · answered by swimmin4ever 1 · 0⤊ 0⤋
For a length of 1 ft: 34 ft (70-2=68/2=34)
For a length of 2 ft: 33 ft (70-4=66/2=33)
For a length of 3 ft: 32 ft (70-6=64/2=32)
2007-02-23 21:45:52 · answer #3 · answered by tcu_twin 1 · 0⤊ 0⤋
The perimeter of a rectangle will have 4 sides so....
1ft length X two sides = 2ft. That leaves 68 ft for the other two sides. 68 / 2 = 34ft. 34+34+1+1=70ft. The width of other rectangles can be obtained the same way. Perimeter minus 2X length = 2X width.
2007-02-23 21:53:06 · answer #4 · answered by Electro-Melon 2 · 0⤊ 0⤋
The perimeter of a rectangle equals two times the length plus two times the width.
P = 2L + 2w
Just plug the information you have into the equation.
ONE FOOT -
we know that:
P = 70ft
L = 1ft
we need to find 'w'
70 = 2(1) + 2w (multiply first)
70 = 2 + 2w (subtract 2 from both sides)
68 = 2w (divide both sides by 2)
34 = w
So...the width would be 34ft
TWO FEET -
we know that:
P = 70ft
L = 2ft
we need to find 'w'
70 = 2(2) + 2w
70 = 4 + 2w
66 = 2w
33 = w
So...the width would be 33ft
THREE FEET -
we know that:
P = 70ft
L = 3ft
we need to find 'w'
70 = 2(3) + 2w
70 = 6 + 2w
64 = 2w
32 = w
So...the width would be 32ft
2007-02-23 21:51:35 · answer #5 · answered by bezi_cat 6 · 0⤊ 0⤋
You need to work with ONE LENGTH at a time.
I will use one of the lengths given for you to use as a guide for the other two.
Ready?
You will also need the perimeter of a rectangle formula.
P = 2L + 2W
We know the perimeter = 70 feet.
We do not know the width. I will call the width x.
Width = x. When we find x, we'll find our width.
I will use the length of 3 feet.
Plug and chug is your ticket to the answer.
P = 2L + 2W
70 feet = 2(3feet) + 2x
70 feet = 6 feet + 2x
70 feet - 6 feet = 2x
64 feet = 2x
64 feet divided by 2 = x
32 feet = x.
The width is 32 feet when the length = 3 feet.
Now, you do the same for the other two length measurements.
Guido
2007-02-23 21:50:01 · answer #6 · answered by Anonymous · 0⤊ 0⤋
the width of the rectangle must be 34ft if the lengthe is 1 ft. 33ft if its 2 ft. and 32ft if its 3 ft.
2007-02-23 21:46:55 · answer #7 · answered by ctem 1 · 0⤊ 0⤋
P=2w+2l, or in other words, perimeter=width times 2+length times 2.
sooo....
70=2(1)+2w
70=2+2w
70-2=2w
68=2w
34=w
the answer for the first one is 34ft
#2: using the same formula
70=2(2)+2w
70=4+2w
70-4=2w
66=2w
33=w
the answer for the second one is 33ft
#3: again using the same formula
70=2(3)+2w
70=6+2w
70-6=2w
64=2w
32=w
the answer for the last one is 32ft.
please don't copy my answers and try to understand them instead. thanx.
2007-02-23 21:52:44 · answer #8 · answered by this is me! 3 · 0⤊ 0⤋
1 ft 34 ft
2 ft 33 ft
3 ft 32ft
2007-02-23 21:45:05 · answer #9 · answered by richardwptljc 6 · 0⤊ 0⤋
70=2(W+L)
W+L=35
W=35-L
W=35-1=34
W=35-2=33
W=35-3=32
2007-02-23 22:19:48 · answer #10 · answered by Mohsen J 2 · 0⤊ 0⤋