The speed of sound in water is 1498 m/s. A sonar signal is sent straight down from a ship at a point just below the surface of the water surface, and 1.80 seconds later, the reflected signal is detected. How deep is the water?
Please help me with this problem.
I don't understand it.
2007-02-23 13:31:22 · 4 answers · asked by swimmertommy 1 in Science & Mathematics ➔ Physics
D=RT
1498 m/s X 1.8 s / 2 = 1348.2 m
Divide by 2 because the signal travled down and then up
2007-02-23 13:36:16 · answer #1 · answered by John S 6 · 0⤊ 0⤋
s=ut + 1/2 at2 (t square), speed of sound is assumed to be constant, therefore no accelaration.. so s=ut.
s= 1498 x (1.8/2)
therefore s = 1348.2 m
time is divided by two as the wave is reflected
2007-02-23 14:20:44 · answer #2 · answered by davE D 1 · 0⤊ 0⤋
So glad that I found this question already answered! It's like you've read my thoughts!
2016-08-23 19:10:36 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Can you give more info?
2016-09-21 01:19:43 · answer #4 · answered by ? 4 · 0⤊ 0⤋