you know you wanna see this........?

Question

the unknown di protic acid has an equivalent weight of 139.42 g/equiv, its average molecular weight is
g/mol and g would be required to make 100.00 mL of a 1.50 N solution.


2

If the stockroom fails to dry the KHP to remove the waters of hydration, the student's calculated concentration
for the standardized base will be

(low, high, or unaffected)
A drop of NaOH is hanging from the buret tip before the titration of KHP. Once the student begins the titration that drop falls into the KHP solution. The calculated concentration for the standardized base wil be
(low, high, or unaffected)

Answer 1

For 1st prob, a diprotic acid provides twice as much H+ as a monoprotic acid, and has a eqvt weight of 1/2 its molecular weight. So mol wt=279 g.

For 1L of a 1.5N solution, 3/4 moles would be needed.
For 0.1 L, 0.075 moles are needed or 21 g.

Cant help you on 2, dont know what KHP is

Answer 2

You need to stop posting these questions online.

Dr. Edwards