English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

Are the following lines parallel, perpendicular, or neither? L1 with equation x – 4y = 20 L2 with equation 4x + y = 4

2007-02-23 12:59:32 · 5 answers · asked by squatincat 1 in Science & Mathematics Mathematics

5 answers

I tried it out by substituting numbers in for x and y and the lines intersect, but not at a right angle, so they are neither.

2007-02-23 13:07:07 · answer #1 · answered by Mathlady 6 · 0 0

L1: x - 4y = 20

=> y = -1/4x - 5 ===> gradient is -1/4

L2: 4x + y = 4

=> y = -4x + 4 ===> gradient is -4

To be parallel, gradient must be the same. To be perpendicular, gradient of 1st line must be (-1/m) of the 2nd line (m).

Both lines' gradients do not satisfy these condition. They are neither parallel nor perpendicular

2007-02-23 21:09:23 · answer #2 · answered by Anonymous · 0 0

You have to remember that in order to know if they are perpenticular or parallel you have to know their slope.

First, put your equations in this form:
y = mx + b

Then, look at their slopes
m = slope

If m of L1 = m of L2 ---> lines are parallel
if m of L1 * m of L2 = -1 ---> lines are perpenticular

2007-02-23 22:53:34 · answer #3 · answered by l77onica 2 · 0 0

put them into y=mx+b form...

so x-4y=20
is... y=-1/4x-5

and 4x+y=4
is y=4x+4

so yes they are perpendicular because their slopes are opposite integers

2007-02-23 21:27:57 · answer #4 · answered by meeepaulinee 2 · 0 0

ummmmmmmm i dont know

2007-02-23 21:02:51 · answer #5 · answered by ~Zaiyonna's Mommy~ 3 · 0 0

fedest.com, questions and answers