Enter answer in the general form
ax+by=c
2007-02-23 12:41:27 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
first you use the point slope form
(y-ysub1)=m(x-xsub1)
substitute your point into xsub1,ysub1 and the slope for m
you get
(y- (-5)) = -3/2 (x-(-4))
(y+5) = -3/2 (x+4)
rearranging this you get:
y= (-3/2)x - 11 --> in the form y= mx+b
or dividing both sides by 2 you get
2y = -3x - 22
then transposing you get
3x + 2y = -22 --> ax+by = c
2007-02-23 12:49:47 · answer #1 · answered by niq_mau 2 · 1⤊ 0⤋
When you do any questions like this use the equation for a straight line:
y(x) = mx + b where m is the slope and b is the y-intercept
You are given the slope = -3/2 == m
So y(x) = -3x/2 + b
And if it has to pass thru the point (-4,-5) then
y(-4) = -3(-4)/2 + b = -5
Solve for b and you have it: b = -5 - 6 = -11
So then y(x) = -3x/2 - 11; but in general form
-3x/2 - y = -11
multiply both sides by -2
3x + 2y = 22
2007-02-23 20:53:33 · answer #2 · answered by kellenraid 6 · 0⤊ 0⤋
y=mx+b
y = (-3/2)x + b
-5 = (-3/2)(-4) + b
-5 = 12/2 + b
-5 = 6 + b
-11 = b
y = (-3/2) x + (-11)
y + 3/2 x = -11
2y + 3x = -22
2007-02-23 20:50:11 · answer #3 · answered by Holden 5 · 0⤊ 0⤋
given slope and points on a line...
start with y=mx + b form and plug #'s
-5 = -3/2 (-4) +b
-5 = 6 + b
b= -11
-3/2x -11 = y
-3/2x -y = 11
2007-02-23 20:46:07 · answer #4 · answered by Joshua B 2 · 1⤊ 0⤋
y=mx+b
y = (-3/2)x + b
-5 = (-3/2)(-4) + b
-5 = 12/2 + b
-5 = 6 + b
-11 = b
y = (-3/2) x + (-11)
y + 3/2 x = -11
2y + 3x = -22
2007-02-23 20:43:46 · answer #5 · answered by ~Zaiyonna's Mommy~ 3 · 1⤊ 2⤋
y + 5 = -3/2(x + 4)
So
x + (2/3)y = -22/3
or 3x + 2y = -22
2007-02-23 20:47:22 · answer #6 · answered by Bhajun Singh 4 · 1⤊ 0⤋