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this formula was formulated by Einstien.

2007-02-23 12:38:52 · 2 answers · asked by Dexter P 1 in Science & Mathematics Physics

2 answers

go read

http://en.wikipedia.org/wiki/Special_relativity

Short answer: you redefine momentum as gamma mv. Energy is the time component of the momentum 4-vector. Like any four vector, it's magnitude is invariant under Lorentz transformations.

E^2 - (pc)^2 = m^2c^4

In the limit that p = 0, this gives you E = +- mc^2.

2007-02-23 12:49:45 · answer #1 · answered by Anonymous · 0 0

As simple as possible:

Newtonian mechanics had the energy formula as E=1/2MV^2.
Unfortunately, if we set the velocity (V) to zero, the energy of the mass (M) is also zero. We now know that this obviously is not correct as evidenced by nuclear reactions and the resultant energy obtained from the mass.
Einstein formulated this same energy, based on the Lorentz Factor and dependent on Einstein's deduction that all reference systems would be valid and all would measure the speed of light exactly the same, as E=MC^2/sqrt1-(V^2/C^2). If we simply set the velocity to zero in this formula, we have E=MC^2 divided by sqrt1-(0) or the more familiar E=MC^2.

2007-02-23 14:28:05 · answer #2 · answered by LeAnne 7 · 0 0

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