In how many different orders can the names of the candidates be printed on a ballot?
2007-02-23 12:18:27 · 7 answers · asked by juliandbn 1 in Science & Mathematics ➔ Mathematics
720 ( 6 x 5 x 4 x 3 x 2 x 1)
The first name can go in any one of the six positions on the ballot.
The second name in one of the remaining 5
The third name in one of the remaining 4
The fourth name in one of the remaining 3
The fifth name in one of the remaining 2
The sixth name in the only place remaining
2007-02-23 12:22:06 · answer #1 · answered by Trevor 7 · 0⤊ 0⤋
6! = 6 * 5 * 4 * 3 * 2 * 1 = 720 different orders
2007-02-23 12:22:46 · answer #2 · answered by Bhajun Singh 4 · 0⤊ 0⤋
=6!=720
2007-02-23 12:22:04 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋
6! = 2*3*4*5*6 = 720
2007-02-23 12:24:20 · answer #4 · answered by FowlFirehead314 1 · 1⤊ 0⤋
6!= 720
2007-02-23 12:23:06 · answer #5 · answered by kash 3 · 0⤊ 0⤋
maybe 36
2007-02-23 12:20:37 · answer #6 · answered by ~Zaiyonna's Mommy~ 3 · 0⤊ 0⤋
alphabetically,hottest, ugliest, oldest, months born in, hair color, eye color...ya know and the list could go on...
2007-02-23 12:21:35 · answer #7 · answered by cutiepiy 2 · 1⤊ 0⤋