The speed that the boat is traveling has to take into account the current speed (C).
So when going upstream it goes (15-C)kph, and when it goes downstream, it goes (15+C)kph.
But we also know that 4(15-C) = 15+C, since the boat goes four times as far downstream than upstream.
60 - 4C = 15 + C or 45 = 5C so the current is 9kph.
The boat goes 24kph downstream to 140km in 5.83 hours.
The boat goes 6 kph upstream to 35km in 5.83 hours.
Sometimes the simplest solution is the best. :o)
2007-02-23 11:39:23
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answer #1
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answered by Anonymous
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d=rt, so t=d/r. Let x be the change in rate of the boat when its going upstream or downstream. since we know that the boat can go upstream for 35 km in the same time it takes to go 140 km downstream we can set an equality using t=d/r. So, since time is the same, 35/(15-x)=140/(15+x). we are using (15-x) and (15+x) for the rate downstream and upstream respectively. Since the current of the river will speed the boat up as much as it will slow it down, the equality will work. when you solve the equation you will get x=9. since when the boat goes downstream it speeds up by x kph, its speed when its going downstream is 15kph+9kph..which is 24
2007-02-23 11:37:03
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answer #2
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answered by someone 2
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The velocity of the boat going upstream is the still water speed MINUS the velocity of the water.
V_up = V_still - V_water
The velocity of the boat going down stream is the still water speed PLUS the velocity of the water.
V_down = V_still + V_water
From the other info we know:
t_up = 35/V_up
t_down = 140/V_down
we also know that:
t_up = t_down
35/V_up = 140/V_down
or
35*V_down = 140*V_up
35(15 + V_water) = 140*(15 - V_water)
you'll find:
V_water = 9kph
so V_up = 15 + 9 = 24
2007-02-23 11:33:51
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answer #3
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answered by Anonymous
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Write your equation. Let the river speed be x then the time to go upstream is 35/ (15 - x) and the time to go downstream is 140/(15+x)
Set these two functions equal and solve for x
35/(15-x) = 140/(15+x)
(15+x)/140 = (15-x)/35
15/140 + x/140 = 15/35 - x/35
x(1/35 + 1/140) = 15/35 - 15/140
x = (15/35 - 15/140) / (1/35 + 1/140)
x = 9kph
So the river is moving at 9kph
when the boat moves downstream it is traveling at 9 + 15 = 24kph with respect to the ground.
2007-02-23 11:30:21
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answer #4
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answered by rscanner 6
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net velocity = boat velocity plus stream velocity
this is a (non-relativistic) vector equation
combine that with
v=d/t
upstream case:
35km/t = 15 kph - vstream
where vstream is the magnitude of the stream velocity,
and we subtract in this case since we're going upstream
downstream case:
140km/t = 15 kph + vstream
now we have two equations with two unknowns (t and vstream)
140 km/t = 15 kph + vstream
35 km/t = 15 kph - vstream
if we add these equations together to cancel vstream we get:
175 km/t = 30 kph
thus t = 175 km / 30 kph = 175/30 hr
the net downstream speed will be
140 km / t and we now know t, so
140 km / (175/30) hr = (2*2*2*3*5*5*7)/(5*5*7) kph =
24 kph
2007-02-23 11:31:09
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answer #5
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answered by Anonymous
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s = 15 kph
r = river speed
140 = (s+r)t ( river flow increases speed)
35 = (s -r )t (upriver travel is slowed by river speed)
Now 35 * 4 = 140
So 140 = 4(s-r)t
So: 4(s-r)t = (s+r)t
Factor out t
4(s-r) = s+r
4s - 4r = s+r
3s = 5r
s = speed = 15kph
45 = 5r
r = 9
So the boat travels 24 kph downstream and 6 kph upstream.
2007-02-23 11:29:20
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answer #6
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answered by John T 6
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r = rate of current
(15 + r)(35) = (15 - r)(140)
15 + r = (15 - r) (4)
15 + r = 60 - 4r
5r = 45
r = 9
current = 9, speed = 15+9 = 24
2007-02-23 11:27:00
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answer #7
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answered by richardwptljc 6
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r = rate of current
(15 + r)(35) = (15 - r)(140)
15 + r = (15 - r) (4)
15 + r = 60 - 4r
5r = 45
r = 9
current = 9, speed = 15+9 = 24
2007-02-23 11:28:05
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answer #8
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answered by ~Zaiyonna's Mommy~ 3
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2016-11-25 19:53:30
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answer #9
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answered by Anonymous
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15 kmph boat speed + stream = 140 km
15kmph boat speed - stream = 35 km
------------------------------------------------------ (add two equations)
30 kmph speed = 175 km
time = 5.83333
140 = rate (5.83333)
RATE = 24
2007-02-23 11:30:19
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answer #10
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answered by csucdartgirl 7
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