Perform the indicated divisions. 8x^3 - 6x^2 + 2x / 4x + 1
2007-02-23 09:41:35 · 7 answers · asked by Mr.Archie G 2 in Science & Mathematics ➔ Mathematics
8x^3 - 6x^2 + 2x / 4x + 1
I SUPPOSE "8x^3 - 6x^2 + 2x" IS OVER "4x + 1".
SO, "8x^3 - 6x^2 + 2x" COULD BE FACTOR TO THIS:
2x(4x^2 - 3x + 1)
WELL, THIS IS AS FAR AS IT CAN BE FACTORED WHICH WILL CONCLUDE TO THIS:
2x(4x^2 - 3x + 1) / 4x + 1
UNLESS YOU DID A MISTAKE AND MEANT THIS:
8x^3 - 6x^2 - 2x
THIS WILL YEALD TO:
x(8x^2 - 6x - 2)
AND THEN
x(2x - 2)(4x + 1)
AND THE FINAL ANSWER WILL BE:
x(2x - 2)
SINCE THE TWO "4x + 1" CANCEL OUT.
2007-02-23 09:44:21 · answer #1 · answered by Mutual Help 4 · 0⤊ 1⤋
Ironduke (1st answer) your element is incorrect. 8x^3-6x^2+2x isn't equivalent to (2x)(4x +a million)(x-a million) 2x (4x +a million)(x-a million) = 2x (4x^2 -4x +x -a million) = 2x(4x^2 -3x -a million) = 8x^3 -6x^2 -2x <----- be conscious the -2x, that is no longer +2x
2016-11-25 19:42:50 · answer #2 · answered by tubb 4 · 0⤊ 0⤋
if the original problem is supposed to written as (8x^3-6x^2+2x)/
(4x+1), then the solution is 2x(x-1)
2007-02-23 09:58:55 · answer #3 · answered by Robert G 2 · 0⤊ 0⤋
greatest common factor out a 2x
2x(4x^2- 3x +1) / 4x+1
unfoil
2x(4x +1) (x-1) / 4x +1....then cancel 4x +1 on top and bottomw for answer of 2x(x-1)....
BUT the original problem would have to be 8x^3 -6x^2 -2x for this all to work....if thats not a typo, then it cannot be solved.
2007-02-23 09:47:22 · answer #4 · answered by K. 3 · 0⤊ 2⤋
8x³ - 6x² + 2x / 4x + 1 =
2x² - 2x = 2x(x-1)
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2007-02-23 11:13:00 · answer #5 · answered by aeiou 7 · 0⤊ 0⤋
2x(4x^2-3x+1)/4x+1
2007-02-23 09:47:47 · answer #6 · answered by mikrodimitris 3 · 0⤊ 1⤋
2x^2 -2x remainder: (4x/4x+1)
2007-02-23 09:50:22 · answer #7 · answered by kash 3 · 1⤊ 1⤋