Perform the indicated divisions x^2 - 2x - 35 / x + 5?
2007-02-23 09:34:48 · 11 answers · asked by Mr.Archie G 2 in Science & Mathematics ➔ Mathematics
x^2 - 2x - 35 / x + 5
I SUPPOSE "x^2 - 2x - 35" IS OVER "x + 5"
OK, THE TOP PART OF THE FRACTION COULD BE FACTORED TO: (x - 7)(x + 5)
SO THIS IS HOW THE FRACTION SHOULD LOOK NOW:
(x - 7)(x + 5) / x +5
SO NOW, BOTH "x + 5" COULD BE CALCELLED OUT WHICH WILL JUST LEAVE YOU WITH "x - 7".
THE ANSWER IS...x-7
2007-02-23 09:37:33 · answer #1 · answered by Mutual Help 4 · 1⤊ 0⤋
x² - 2x - 35 / x + 5 = x - 7
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2007-02-23 19:42:31 · answer #2 · answered by aeiou 7 · 0⤊ 0⤋
Factorize: x^2-2x-35 = (x-7)(x+5)
Answer: x-7 after dividing
2007-02-23 17:38:25 · answer #3 · answered by gumtrees 3 · 1⤊ 0⤋
step 1: factor x^2-2x-35= (x-7)(x+5)
step 2: perform division
[(x-7)(x+5)]/(x+5) = (x-7)
2007-02-23 17:37:42 · answer #4 · answered by Michael 2 · 1⤊ 0⤋
Unfoil x^2-2x-35 to (x-7)(x+5)
Cacel the (x+5) on the top with (x+5) on bottom so answer in x-7
2007-02-23 17:38:25 · answer #5 · answered by K. 3 · 1⤊ 0⤋
I assume yo umean
(x^2-2x-35)/(x+5) ( ) are important.
(x+5)(x-7)/(x+5) cancel x+5 from numerator & denominator
x+7
2007-02-23 18:07:19 · answer #6 · answered by yupchagee 7 · 0⤊ 0⤋
x-7 no remaning
multiply x to (x+5) u will get x^2+5x subtract from x^2-2x-35 u will have -7x-35 then multiply -7 to x+5 u will get -7x-35 then subtract from -7x-35 will get 0 remaining
(x+5)(x-7)
2007-02-23 17:41:37 · answer #7 · answered by SHALO 2 · 1⤊ 0⤋
=(x-7) So x^2 -2x-35 = (x+5)*(x-7)
2007-02-23 17:40:24 · answer #8 · answered by santmann2002 7 · 1⤊ 0⤋
Factor the top
(x-7)(x+5)/(x+5)
so the x+5 cancels,
x-7 is the answer
2007-02-23 17:37:05 · answer #9 · answered by leo 6 · 1⤊ 0⤋
= (x - 7). (x + 5) / (x +5)
= x - 7
2007-02-23 17:43:22 · answer #10 · answered by Como 7 · 0⤊ 0⤋