The speed of light is 3.0*10^8m/s. The speed of sound is 344m/s. A flash of lightning occurs in a storm 1.0*10^4m away. How many seconds does it take for us to see the lightning and hear the thunder?
2007-02-23 09:13:53 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
To see the lightning:
(1 * 10^4 m) / (3 * 10^8 m/s) =
(1 m) / (3 * 10^4 m/s) =
(1/3) * 10^(-4) s =
0.0000333... s
To hear the thunder:
(1 * 10^4 m) / (344 m/s) =
10000 m / 344 m/s =
29,0698 s (approx.)
2007-02-23 09:21:27 · answer #1 · answered by jcastro 6 · 0⤊ 0⤋
It takes 3.33 *10^-5 s. to see the lightning.
It takes 29.07 s. to hear the thunder.
2007-02-23 09:21:36 · answer #2 · answered by kash 3 · 0⤊ 0⤋
The flash will reach you in:
1.10^4 / 3.10^8 = 3.33.10^-5 s
While the sound will reach you in:
1.10^4 / 344 = 29.07 s
I hope this helps?!
2007-02-23 09:46:52 · answer #3 · answered by TK_M 5 · 0⤊ 0⤋
V=d/t, so t=d/v. Solve for the time in each case, and you have your answer.
2007-02-23 09:22:53 · answer #4 · answered by thom1102 2 · 0⤊ 1⤋