A proton moving freely in a circular path perpendicular to a constant magnetic field takes 1.40 µs to complete one revolution. Determine the magnitude of the magnetic field.
2007-02-23 08:41:49 · 3 answers · asked by Livelife 1 in Science & Mathematics ➔ Physics
The centrifugal force is equal to F = mv^2/r must equal the force due to the field F= q v B
qvB=mv^2/r or qB/m=v/r and v=2 pi r /1.4µs
2007-02-23 13:32:48 · answer #1 · answered by meg 7 · 0⤊ 0⤋
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2016-11-25 19:38:44 · answer #2 · answered by ? 4 · 0⤊ 0⤋
You can't.
You need to know ths size of the path.
2007-02-23 08:46:05 · answer #3 · answered by Anonymous · 0⤊ 0⤋