chem problem, plz help?

Question

Al2(SO4)3•18H2O is used to help dyes adhere to clothes. One way to make this compound is represented in the following equation. You must report your answers to the correct number of significant figures.
Al(OH)3 + H2SO4 + H2O → Al2(SO4)3•18H2O

a) Balance this equation
b) Determine the maximum yield of Al2(SO4)3•18H2O that could be obtained by starting with 25.0 g Al(OH)3, 50.0 g H2SO4 and unlimited water.

c) If 3.2 g of Al2(SO4)3•18H2O form, what is the percent yield for this reaction?

Answer 1

a) 2Al(OH)3 + 3H2SO4 + 16H2O --> Al2(SO4)3•18H2O
b) Al= 27g/mole, O = 16 g/mole , S= 32 g/mole
Al2(SO4)3•18H2O = 666 g/mole
H2SO4 = 98g/mole 50g = 0.51 mole
Al(OH)3 = 78 g/mole 25 g = 0.32 mole

Al(OH)3 is limiting reagent 0.32 moles would use 3/2 of H2SO4
= 0.24 mole

so should expect 0.32 mole (1:1 relationship) of Al2(SO4)3•18H2O = 0.32 * 666 = 213.1 g

c) % yield = 3.2g/213.1 *100 = 1.5%

Answer 2

Oh gee, I never understood balancing equations. I still don't even though we do it all the time. I tried my best to balance the equation, but I'm afraid I'm doing something wrong. Sorry, I couldn't come up with anything.:(

Answer 3

i think of you will possibly be able to desire to comprehend the belief-approximately "moles" in chemistry previously you study a thank you to unravel your concern. I provide under the reason of "mole": QUOTE: what's a Mole? A mole is the quantity of organic substance containing a similar kind of chemical gadgets as there are atoms in precisely 12 grams of carbon-12 (i.e., 6.023 X 10^23). This comprises the attractiveness of two dictates -- the dimensions of atomic hundreds and the value of the gram. the two have been widely used by potential of international contract. in the past, the connotation of "mole" replaced into "gram molecular weight." cutting-edge utilization has a tendency to stay with the term "mole" to an quantity containing Avogadro's kind of in spite of gadgets are being seen. for this reason, this is a threat to have a mole of atoms, ions, radicals, electrons, or quanta. This utilization makes pointless such words as "gram-atom," "gram-formula weight," etc. All stoichiometry surely relies on the assessment of the kind of moles of substance. the main person-friendly comprises the dimensions of mass. for this reason 25.000 grams of water will comprise 25.000/18.0.5 moles of water, 25.000 grams of sodium will comprise 25.000/22.990 moles of sodium. UNQUOTE Why do no longer we in simple terms follow gadgets like grams (and nanograms and kilograms, etc.)? the respond is that moles provide us a relentless approach to transform between atoms/molecules and grams. it fairly is in simple terms a handy unit to apply whilst appearing calculations. ok... you will possibly no longer discover it too handy once you're first discovering a thank you to apply it, yet as quickly as you alter into acquainted with it, a mole would be as favourite a unit as, say, a dozen or a byte. concern verify the kind of moles of CO2 in 454 grams. answer First, look up the atomic hundreds for carbon and oxygen from the Periodic table. The atomic mass of C is 12.01 and the atomic mass of O is sixteen.00. The formula mass of CO2 is: 12.01 + 2(sixteen.00) = 40 4.01 for this reason, one mole of CO2 weights 40 4.01 grams. This relation components a conversion ingredient to flow from grams to moles. using the ingredient a million mol/40 4.01 g: moles CO2 = 454 g x a million mol/40 4.01 g = 10.3 moles answer 10.3 moles CO2 you are able to now resolve for Boron.

Answer 4

do your homework alone