math question?

Question

[square root(x + 7)] -x = 5

Answer 1

[square root(x + 7)] -x = 5
=>
[square root(x + 7)] = 5 + x

=> squaring both sides
(x + 7) = (5 + x)^2
=>
(x + 7) = x^2 + 10x + 25
=>
x^2 + 9x + 18 = 0
=>
(x+6)(x+3) = 0
=>
x = -6 or x = -3

Answer 2

So first you move the x over

square root x + 7 = x+5

Then, square each side to get rid of the radical.

x+7 = (x+5)^2--squared

then foil (x+5)(x+5) which is x^2 +10x +25
so the whole equations is:

x+7 = x^2 + 10x+ 25...

then subtract x and 7 fromeach side to ge t

0 = x^2 + 9x + 18

then find x by unfoiling (FOIL is first, outside, inside, last, if you didn't know)

(x + 6) (x + 3) = 0

Then set each paranthesis = 0 so your x values are

x= - 6, - 3


Happy to help

Answer 3

sq root(x + 7) - x = 5
sq root(x + 7) = 5 + x

Squaring both sides,
x + 7 = (5 + x)^2
x + 7 = 25 + 10x + x^2
x^2 + 9x + 18 = 0
(x + 3)(x + 6) = 0
x = -3 or -6

Answer 4

Square both sides and turn it into a quadratic equation.

(x + 7) = x^2 + 10x + 25
0 = x^2 + 9x +18

You can solve your quadratic equation using the quadratic equation or by trial and error. In this case, you only have two integer combinations that multiply to 18, so I'd try those first before resorting to the quadratic equation.

Answer 5

√(x+7)-x=5 add x to each side
√(x+7)=x+5 square both sides
x+7=x^2+10x+25 subtract x+7 drom each side
x^2+9x+18=0
(x+6)(x+3)=0
x+6=0
x=-6
x+3=0
x=-3

x=-3, -6

Answer 6

false

Answer 7

yes it is the object is to find what "X" is

Answer 8

What is x = to