Test. First one done gets best answer award. You must have atleast 90% correct unless someone gets 100%.?

Question

1) Does sin^2X + 1 = Cos^2X
2) Does CotX = SinX/CosX
3) Does SinX + CosX = 1
4) Is Sin^2X + Cos^2X = SinX + CosX
5) Does CotX = Tan^2X
6) Does SinX = 1/SecX
7) What is 1 + Cot^2X?
___a. Sec^2X
___b. CSC^2X
___c. Cot^2X
8) Does CotX * SinX = 1 - SinX
9) Does SinX = 1/(1+CotX)
10) Does (SinX/CotX) * (CscX -1) = 1/(1 + CotX)

FYI, I know the answer, and coinman090388 got it correct. This is not a homework question. Congradulations coinman090388 Once this question has existed for 4 hours, I can vote you as the best. Dedicated to you is a coin collectors question that I posted. It is 10 questions and they are all about U.S. coins and bills. The same rules apply. If you are the first to get this one 90% right and no one gets it 100% right, you win best answer. enjoy my game.

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http://answers.yahoo.com/question/index;_ylt=AjJdI1dMONHj2me8EXIZORnsy6IX?qid=20070223152922AAIaDsu

Answer 1

1) No
2) Yes
3) Yes
4) Yes
5) No
6) No
7) b. CSC^2X
8) Yes
9) Yes
10) Yes

Answer 2

1) no sin^x-1 = cos^2x
2) no cotx = cosx/sinx
3)no sin^2x +cos^x = 1
4)no
5) tan 2x= sin2x/cos2x = 2sinx cosx / cos^2x-sin^2x
but cotx = cosx/sinx they are not equal
6)no sinx = 1/csc x
7)answer b csc^2x
8)cosx / sin x * sinx = cosx not eual 1- sinx wrong
9) no of course sin^2x = 1 / ( 1 + cot^2x) it doesnt go without power 2
10) sinx / (cosx/sinx) * ( 1 / sinx - 1 ) = sin^2x /cosx * (1-sinx)/sinx not equal right side
they are all wrong who messed up that much????

Answer 3

1. No
2. No
3. No
4. No
5. No
6. Yes
7. a)sec^2x
8. No
9. No
10. No

Answer 4

1. Do
2. Your
3. Own
4. Freakin
5. Homework
6. Before
7. You
8. Fail
9. Your
10. Class

Answer 5

1) No; cos^2(x) = 1 - sin^2(x)
2) No; sin(x)/cos(x) = tan(x)
3) No; sin^2(x) + cos^2(x) = 1
4) No; sin^2(x) + cos^2(x) = 1, and sin(x) + cos(x) is not equal to sin^2(x) + cos^2(x)
5) No; cot(x) = cos(x)/sin(x), and tan^2(x) = sin^2(x)/cos^2(x)
6) No; sin(x) = 1/csc(x)
7) 1 + cot^2(x) = csc^2(x)
8) cot(x) sin(x) = cos(x), and cos(x) is NOT equal to 1 - sin(x), so the answer is no.
9) 1/(1 - cot(x)) = sin(x)/(sin(x) - 1); the answer is no.

10)

No; let x = pi/4.

LHS sin(pi/4)/cot(pi/4) * csc(pi/4) - 1
= sqrt(2)/2 * (2/sqrt(2) - 1)
= 1 - sqrt(2)/2

RHS = 1/(1 + cot(pi/2)) = 1/2

LHS not equal to RHS

Answer 6

1) No
2) No
3) No
4) No
5) No
6) No
7) b. CSC^2X
8) No
9) No
10) No

Answer 7

Hmmm. Sounds like someone wants us to do homework.

I'll just start off each one.

1) sin^2 + cos^2 = 1
2) sin/cos = tan
3) (sin(45˚)+cos(45˚)= 1.4142135...)
4) see 1 and 3
5) tan^2 = sin^2 / cos^2 = (1+cos^2)/ cos^2
= (1/cos^2) + 1
6) 1/sin = csc
7) 1 + cos^2/sin^2 = 1 + (1-sin^2)/sin^2
= 1 + 1/sin^2 -1 = 1/sin^2 = (1/sin)^2
8) cot = cos/sin
9) 1 / (1+cot) = 1 / (1 + cos/sin) = 1 / ((sin+cos)/sin)
= sin/(sin+cos)
10) (sin^2/cos)*((1/sin)-1) = sin/cos - sin^2/cos =
(sin-sin^2)/cos = (sin/cos)*(1-sin)

Answer 8

I got a bonus check, a free subscription to TV Guide and a Chuck E Cheeses token..

Answer 9

1) sometimes
2) sometimes
3) sometimes
4) sometimes
5) sometimes
6) sometimes
7) b
8) sometimes
10) too confusing

Answer 10

1) no
2) no
3) no
4)no
5)no
6) no no no
7) none its -1
8) no
9) no
10) no