0<3-x<9
-3<-x<6
3>x>-6
-6
2007-02-23 07:58:06
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answer #1
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answered by Anonymous
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0 < 4x +3 - 5x < 9 simplify the middle portion of the inequality
0 < -x + 3 < 9 now subtract 3 from the two ends and also the middle.
-3 < -x < 6 divide by a negative one on each end and also in the middle any time you divide or multiply by a negative number, the inequality signs switch directions.
3 > x > -6 now rearrange the inequality where the smallest number is to the left of the answer.
-6 < x < 3 this says that x would lie somewhere between -6 and 3 noninclusive.
2007-02-23 08:00:48
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answer #2
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answered by Ray 5
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0<4x +3 - 5x<9
0 < -x + 3 < 9 (combine like terms; 4x and -5x are like terms, and become -x)
-3 < -x < 6 (subtract 3; thus 0 becomes -3 and 9 becomes 6)
-6 < x < 3 (divide by -1; because the number you are dividing by is negative, you must switch the inequality signs)
2007-02-23 07:59:42
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answer #3
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answered by infinitys_7th 2
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First do: 0<4x+3-5x
--> 0<3-x
-->x<3 (1)
Then do: 4x+3-5x <9
-->3-x<9
-->x>-6 (2)
From (1) & (2) ---> -6
Hope it helps and vote me a best answer. Thank you
2007-02-23 08:01:25
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answer #4
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answered by hoangtuthichdua2005 1
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0<-x+3<9
0<-x+3-3<9-3
0<-X<6
0>X>-6
2007-02-23 08:12:28
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answer #5
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answered by Dave aka Spider Monkey 7
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1 and 2 both work
2007-02-23 07:58:52
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answer #6
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answered by justme 3
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sub. 3 from both sides, divide to get rid of the neg., flip the sign.
2007-02-23 07:57:14
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answer #7
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answered by Anonymous
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out have to get x by itself by sub. ,mul. ,div. ,or adding everything else
2007-02-23 07:58:14
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answer #8
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answered by solochick101 2
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do not forget to graph it.....
2007-02-23 08:00:10
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answer #9
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answered by Frank G 1
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DO YOUR OWN HOMEWORK!
2007-02-23 07:55:31
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answer #10
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answered by Tyler™ 5
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