product A=5$ B=$3 Quantity sold=50 total sales=$180. How many A's and B's are sold? how to compute ? pls help
2007-02-23 07:49:58 · 9 answers · asked by anteater42001 1 in Science & Mathematics ➔ Mathematics
You have enough info to make two formulae:
5A+3B=180
(Some amount of As at $5 each plus some amount of Bs at $3 each, totalling $180)
and
A+B=50
(The amount of As plus the amount of Bs are equal to 50)
You're trying to solve for A and B. Here's one way.
Solve for A in terms of B using the second equation
A=50-B
Substitue in the first equation, solve
5(50-B)+3B=180
250-5B+3B=180
70=2B
35=B
Put B back in the other equation, solve for A
A+35=50
A=15
So 35 Bs sold and 15 As sold.
2007-02-23 07:59:05 · answer #1 · answered by Juice 1 · 0⤊ 0⤋
Well, the number of A's and B's added together is 50, right? So, let x = number of A's and y = number of B's
x + y = 50
Now if I so x A's, how much did that make? $5 for each, right? So
5x + 3y = 180 Now x + y = 50 means y = 50 - x so
5x + 3(50 - x) = 180
5x + 150 - 3x = 180
2x = 180 - 150
2x = 30
x = 15
15 + y = 50
y = 50 - 15
y = 35
HTH
Charles
2007-02-23 16:00:53 · answer #2 · answered by Charles 6 · 0⤊ 0⤋
Let a and b be the number of units sold each of products A and B.
We know two things
a + b =50
5a + 3b =180
Using the first equation
a = (50-b)
Plug that into the second equation
5*(50-b) + 3b = 250 - 5b + 3b = 250 - 2b = 180
-2b = -70
b = 35
a = 50- 35 = 15
2007-02-23 15:54:19 · answer #3 · answered by Michael C 3 · 1⤊ 0⤋
you have to set up a system of equations.
let a = # of A sold
let b = # of B sold
a+b=50
5a + 3B = 180
solve for a in the 1st equation : a= 50-b
substitute 50-b for A in the 2nd equation.
5(50-b) + 3b = 180
250-50b+3b = 180
-47b +250 = 180
b=1.50
substite for b inj the 1st equation.
a+b=50
a+1.50 = 50
a=48.50
2007-02-23 15:59:43 · answer #4 · answered by Ari 6 · 0⤊ 0⤋
Simple substitution problem,
5a + 3b = $180
a + b = 50
solve for a
a = 50 -b
5(50-b) + 3b = 180
250 -5b + 3b = 180
-2b = -70
b = 35
a = 50 - 35
a = 15
I can't believe I still remember how to do this!
2007-02-23 15:56:55 · answer #5 · answered by Anonymous · 0⤊ 0⤋
I don't think that's enough information to setup the equation. You'll probably need to know of the 50 sold which were A and B
2007-02-23 15:54:07 · answer #6 · answered by caflyer25 2 · 0⤊ 1⤋
x - number of A's
y - number of B's
x + y = 50
5x + 3y = 180
2007-02-23 15:53:09 · answer #7 · answered by Anonymous · 1⤊ 0⤋
You Should Pay Attention In Class And Do YOUR Homework!
2007-02-23 15:58:26 · answer #8 · answered by Tyler™ 5 · 0⤊ 1⤋
????
2007-02-23 15:52:01 · answer #9 · answered by Dopie 1 · 0⤊ 2⤋