absolute value of ((3x+2)/(x-1))=4
2007-02-23 07:35:00 · 5 answers · asked by phoenixmkm 1 in Science & Mathematics ➔ Mathematics
Case 1: positive four
(3x + 2) / (x-1) = 4
3x + 2 = 4x - 4
2 = x - 4
x = 6
Case 2: negative four
(3x + 2) / (x-1) = -4
3x + 2 = -4x + 4
7x + 2 = 4
7x = 2
x = 2/7
2007-02-23 07:41:29 · answer #1 · answered by Michael C 3 · 0⤊ 0⤋
you set up 2 equations.
3X^2+X-2 = 4
3X^2 +X -2 = -4
now factor or use the quadratic formula to solve for X. In these problems, u MUST check(1 might not work)
2007-02-23 15:41:05 · answer #2 · answered by Ari 6 · 0⤊ 0⤋
if you square both sides, this gets rid of the absolute values. solve for x, which gives 2/7 and 6. plugging 2/7 in gives I-4I=4, and 6 gives I4I=4. Both of these are solutions to the original problem.
2007-02-23 16:15:10 · answer #3 · answered by Robert G 2 · 0⤊ 0⤋
Mult by x-1
3x+ 2 = 4(x - 1)
3x + 2 = 4x - 4
x = 6
2007-02-23 15:38:56 · answer #4 · answered by richardwptljc 6 · 0⤊ 0⤋
3x + 2 = 4
--------
x-1
x-1 * 3x + 2 = 4(x-1)
--------------
x-1
3x + 2=4x – 4
3x – 4x = -4-2
-x = -6
-x = -6
-1 -1
X = 6
and so the abosolute value of positive 6 is positive 6
2007-02-23 15:58:54 · answer #5 · answered by shamira p 1 · 0⤊ 0⤋