Solving hypergeromteric?

Question

I simply cannot remember how to actually calculate the P(x) = 3 choose 1 times 2 choose 2, divided by 5 choose 3.

P(X) =

(3) (2)
1 2
--------- = ????
(5)
3
I know how to set that up, however actually calculating it i don't know how.
Can someone help?

Answer 1

n chose k = n!/{k!(n-k)!}

So 3 chose 1 = 3!/{1!(3-1)!}
= 3

2 chose 2 = 2!/{2!(2-2)!}
= 1 (remember that 0! = 1)

5 chose 3 = 5!/{3!(5-3)!}
= 10

So P(X = 1) = 3*1/10
= 0.3

Answer 2

P(x) = (3/1)(2/1)(1/2)/((5/1)(4/2)(3/3) = 3/10

Answer 3

what is the problem and what do you want to be solved ?

do you want to know the function of the hypergeometric function ?

then look here

http://en.wikipedia.org/wiki/Hypergeometric_distribution