2007-02-23 06:18:13 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Add +6 to both side
square root (2x+ 6)=6
Take square of both sides
(2x+6) = 36
2x=30
x=15
2007-02-23 06:23:52 · answer #1 · answered by The exclamation mark 6 · 0⤊ 0⤋
sqrt(2x + 6) - 6 = 0
add 6 to both sides
sqrt (2x + 6) = 6
square both sides of the equation
2x + 6 = 36
subtract 6 from both sides
2x = 30
divide both sides by the coefficient of x
x = 15 is the solution.
2007-02-23 06:44:23 · answer #2 · answered by Ray 5 · 0⤊ 0⤋
(√2x + 6) - 6 = 0
(√2x + 6) - 6 + 6 = 0 + 6
(√2x + 6) = 6
(√2x + 6)² = (6)²
2x + 6 = 36
2x + 6 - 6 = 36 - 6
2x = 30
2x/2 = 30/2
x = 30/2
x = 15
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2007-02-23 07:52:38 · answer #3 · answered by SAMUEL D 7 · 0⤊ 0⤋
sqrt(2x + 6) - 6 = 0
sqrt(2x + 6) = 6
2x + 6 = 36
2x = 30
x = 15
2007-02-23 07:37:25 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋
√(2x+6)-6 = 0
√(2x+6)-6+6 = +6
( √(2x+6) )^2= ( 6 )^2
2x+6 = 36
2x = 36-6
2x = 30
x = 15
2007-02-23 06:26:04 · answer #5 · answered by sebourban 4 · 0⤊ 0⤋
√[2x + 6] = 6
2x + 6 = 36
2x = 30
x = 15
2007-02-23 06:27:46 · answer #6 · answered by Como 7 · 0⤊ 0⤋
sqrt of 2x+6^2=6
2x+6=36
2x+6-6=36-6
2x=30
x=15
2007-02-23 07:23:46 · answer #7 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
√(2x+6) = 6
2x+6 = 36
2x = 30
x = 15
2007-02-23 06:22:16 · answer #8 · answered by danrouthier 2 · 2⤊ 0⤋
sqrt(2x+6)-6=0
sqrt(2x+6)=6
srt(2x+6)^2=6^2
(2x+6)=36
2x=30
x=15
2007-02-23 06:24:27 · answer #9 · answered by Michael 2 · 0⤊ 0⤋
x is 16.
2007-02-23 06:23:28 · answer #10 · answered by a2zpupz 1 · 0⤊ 2⤋