Solve √y+16=1 Where y+16 are both under the sr sign?

Answer 1

Square both Sides
y+16=1
y=-15

Answer 2

if they are both under the √ sign, you put parentheses around the argument of the √. you not tell us that y + 16 are both under the √ sign.
suppose in all formulas they use that notation, math books would get really big huh. x + 1 ^2 , where x+1 are both under the ^2 sign . ....


ok now for the problem

√(y+16)=1 ==> y+16 = 1=> y = -15

Answer 3

What you have to do is "undo" operations in reverse order. If you were going to evaluate Root(3+16), you would first add the 16 to the 3, and then square root that. We're going to need to do the undo operation in the reverse order (so deal with the root first, then the add).

To get rid of a square root, you square both side:

Root(y + 16) = 1
Root(y + 16)^2 = 1^2
y + 16 = 1

To get rid of the + 16, you subtract 12 from both sides

(y + 16) - 16 = (1) - 16
y = -15

And there is your answer!

Answer 4

square both sides of your equation and you get

sqrt of y+16^2=1^2
y+16=1
y+16-16=1-16
y=-15

Answer 5

√y + 16 = 1

(√y + 16)² = (1)²

y + 16 = 1

y + 16 - 16 = 1 - 16

y = - 15

- - - - - - - -s-

Answer 6

square bot sides of the equation and get
y+16 = 1
now subtract 16 from both sides
y = -15
check to make sure this gives you a viable answer.

It does work so, y = - 15 is the solution

Answer 7

√(y+16) = 1
(√(y+16) )^2 = ( 1 )^2
y+16 = 1
y = 1-16
y = -15

Answer 8

you square the two sides


y+16 =1

y =-15

Answer 9

sqrt(y + 16) = 1
y + 16 = 1
y = -15

Answer 10

-15