2007-02-23 05:59:46 · 13 answers · asked by savannah_banana03 1 in Science & Mathematics ➔ Mathematics
√108=√2x2x3x3x3
Take out the doubles because they are squares
So take out 2x3
2x3√3
6√3
2007-02-23 06:23:11 · answer #1 · answered by Anonymous · 1⤊ 0⤋
â108 = â [12 x 9] = 3â12 = 3â[3 x 4] = 6â3
2007-02-23 06:25:32 · answer #2 · answered by Como 7 · 0⤊ 0⤋
2 x 2 x 3 x 3 x 3
2007-02-23 06:05:19 · answer #3 · answered by shadow10262000 3 · 0⤊ 1⤋
There are many ways to write this :
â108 = sqrt (2^2 3^3) = 2*3 sqrt 3
= 6 sqrt 3 = 6*3^(1/2) = 6â3.
Any of the expressions in the previous line is an acceptable way of writing the simplification.
Live long and prosper.
2007-02-23 06:02:08 · answer #4 · answered by Dr Spock 6 · 1⤊ 0⤋
find denominators of 108, and determine which ones can be "pulled" out, as square roots of themselves.
Consider:
2*2 * 3*3*3 = 108
which comes to 4 * 9 * 3 =108
Now consider:
sqrt 4 * sqrt 9 * sqrt 3 = sqrt 108
which would leave you with 2 * 3 * sqrt 3 = sqrt 108
or
6* sqrt 3 = sqrt 108
and it's been simplified!
2007-02-23 06:05:18 · answer #5 · answered by wheresdean 4 · 1⤊ 0⤋
sqrt of 108= sqrt of 36 x sqrt of 3= 6 x sqrt of 3
2007-02-23 07:13:37 · answer #6 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
/108= /9 /12= 3/12 = 3/4 /3 = 6/3
the /=radical
2007-02-23 06:35:53 · answer #7 · answered by Anonymous · 0⤊ 0⤋
+sqrt(108) = +sqrt(2*2*3*3*3)= +2*3sqrt(3) = 6â3
Done.
2007-02-23 06:11:48 · answer #8 · answered by Jerry P 6 · 1⤊ 0⤋
â108 = (â4)(â9)(â3) = (2)(3)(â3) = 6â3
Hope that helps ;)
2007-02-23 06:03:00 · answer #9 · answered by MamaMia © 7 · 0⤊ 0⤋
2*2
3*3*3
then take1 nimber from each group which will give 2*3 so the answer is 6
2007-02-23 06:02:52 · answer #10 · answered by Zerro 2 · 0⤊ 1⤋