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An atom of gold weighs 3.25x10^-22. What is the weight of 7000 atoms of gold? Express your answer in scientific notation.

2007-02-23 05:46:36 · 4 answers · asked by Dwight 2 in Science & Mathematics ➔ Mathematics

To Angela: Shut the hell up you stupid whore

2007-02-23 06:33:38 · update #1

7000x3.25x10-22 = 2.275x10^-18

2007-02-23 05:52:42 · answer #1 · answered by Barbara H 5 · 0⤊ 0⤋

Weight = 7000 x 3.25 x 10^(-22)

Weight = 7 x 10Â³ x 3.25 x 10^(-22)

Weight = 22.75 x 10^(-19)

Weight = 2.275 x 10^(-18)

2007-02-23 14:32:43 · answer #2 · answered by Como 7 · 0⤊ 0⤋

W = 7*10^3*3.25*10^-22= 2.275*10^-18

2007-02-23 13:53:14 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋

Shame on you getting other people to do your homework. What you going to do when it comes test time?

2007-02-23 14:00:25 · answer #4 · answered by Angela 3 · 0⤊ 0⤋