I agree......air, like anything else has weight. The more air you cram into the tank the more it will weigh and obviously not tend to flot as readily.
2007-02-23 06:07:55
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answer #1
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answered by Anonymous
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No it would not, as you increase the amount of air in the tank, with the tanks volume remaining the same the weight of the tank and air will increase. Lowering the pressure in the tank below atmoshperic pressure will lighten the tank. In some tanks meant for containing waste oil a lower pressuer jacket is used to surround the oil tank, and a vacum gauge is installed, this allows inspectors to ensure the oil is contained by just checking the vacum. If something damges the inner or outer tank the vaccum gauge will read atmospheric pressure and the tank will have to be inspected.
2007-02-23 13:58:09
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answer #2
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answered by oneirondreamer 3
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No, it would be worse at floating. Adding any mass to the inside of the tank would make it sink further. Increasing the pressure to 100 psi, which is roughly 6.8 times normal atmospheric pressure will make 6.8 times as much weight of air in the tank than before.
The best floating tank would be filled with nothing (a vacuum). Even helium wouldn't be better, because even helium has weight. It's impractical to create a strong vacuum in a large tank though, since it might be more easily crushed.
2007-02-23 14:05:20
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answer #3
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answered by Thomas G 3
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Air has mass or weight and a cylinder of air at 100psi will be heavier than when empty or partly filled so its buoyancy (flotation) would be less.
(This would be the case even with hydrogen .. the lightest gas .. this also has weight).
2007-02-23 19:03:05
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answer #4
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answered by Norrie 7
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Actually LESS flotation. Air has mass. Mass = weight Therefore more air, more weight.
2007-02-23 13:39:20
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answer #5
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answered by ibeboatin 5
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lower pressure is more likely to float for a given substance.
2007-02-23 13:39:46
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answer #6
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answered by romulusnr 5
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seems like it should have less...as the compressed air in the tank would be heavier.
2007-02-23 13:38:00
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answer #7
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answered by Anonymous
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