Complete the square for this problem: x^2-7x+5=0
2007-02-23 04:59:11 · 3 answers · asked by Parks H 2 in Science & Mathematics ➔ Mathematics
x² - 7x + 5 = 0
x² - 7x + 5 - 5 = 0 - 5
x² - 7x = - 5
x² - 7x + 49/4 = - 5 + 49/4
x² - 7x + 49/4 = - 20/4 + 49/4
x² - 7x + 49/4 = 29/4
(x - 7/2)(x - 7/2) = 29/4
(x - 7/2)² = 29/4
√(x - 7/2)² = ± √29 / √4
x - 7/2 = ± √29√4 / √4√4
x - 7/2 = ± √29 √4 / √16
x - 7/2 = ± 2 √29 / 4
x - 7/2 = ± √29/2
x = - 7/2 + 7/2 = 7/2 ± √29/2
x = 7/2 ± √29/2
- - - - - - - - - - - - - - -s-
2007-02-23 06:58:42 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
x² - 7x + 49/4 = -5 + 49/4
(x - 7/2)² = 29/4
x - 7/2 = ± â(29 / 4)
x = 7/2 屉29 / 2
x = (1/2) [ 7± â29 ]
2007-02-23 06:19:30 · answer #2 · answered by Como 7 · 0⤊ 0⤋
(x^2 - 7x + ____ ) = - 5 + ____
(x^2 - 7x + 49/4 ) = - 5 + 49/4
(x - 7/2 )^2 = 29/4
that is it
2007-02-23 05:23:14 · answer #3 · answered by Ray 5 · 1⤊ 0⤋