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Lito pushes a 100-kg box to the right while Mario pushes it to the left with a force of 300 N. How much force should Lito exert to allow the cart to move 1.5 m/s^2 against Mario?

2007-02-23 02:17:51 · 6 answers · asked by Anonymous in Science & Mathematics Physics

6 answers

Force,F=Mass,m x acceleration,a
F = 100 x 1.5
F= 150N
So Lito should exert 150 + 300
= 450N

2007-02-23 02:26:07 · answer #1 · answered by Southpaw 5 · 0 0

if 1 Newtown = 1Kg/1(m/sec²) then 300N=300Kg/(1m/sec²).
We know that Force = Mass X Acceleration so Mario's force = 300N = ?Kg/?a(accelaration in meters per squared seconds).
Since the box is 100Kg then we have 300N=100Kg/?a(accelartion). F=ma or a=F/m so a=300[F]/100[m].
So, a = 300/100 = 3 m/sec².
So Mario is pushing the box at 3 meters per second squared.
If Lito pushes the box back with the same force then since the mass is not changing then lito will accelearate the box at the same rate as Mario, 3 m/sec² (assuming Lito pushes the box 300Newtons) and therefore the box will not move, will stay in place because both are pushing at the same time. For Lito to advance it 1.5 m/sec² he needs to accelerate it 1.5[a] more than Mario, where a is in meter per second squared. 1.5[a] + 3[a] = 4.5[a]. Since the box is still 100kg and a = F[N]/a[m/sec²] then F = mass X acceleration = 100[Kg] X 4.5[m/sec²] = 450 Newtowns.

2007-02-23 10:51:11 · answer #2 · answered by martinezjosei 2 · 0 0

F = ma, so the net force would have to be F = (100 kg)(1.5 m/s^2) = 150 N. So Lito must push the box with 150 N greater force than Mario, or 450 N.

2007-02-23 10:24:42 · answer #3 · answered by Bhajun Singh 4 · 0 0

This is an application of Newton's secondlaw. If we say that the Force applied by lito is Fl and the Force applied by Mario to be Fm(=300N).

Then Fl-Fm= Mass of box * acceleration.

= 100*1.5+300= 150+300= 450N

Lito needs to push with 450N.

2007-02-23 10:29:22 · answer #4 · answered by The exclamation mark 6 · 0 0

450N easily if there is no friction on the ground...

2007-02-23 15:23:12 · answer #5 · answered by Pulkit 1 · 0 0

no, i won't

2007-02-23 12:17:17 · answer #6 · answered by chicago cub's bat bunny 5 · 0 0

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