Find the unknown length in each given right triangle?

Question

1. leg = 12, leg = 5, hypotenuse =

2. leg = 9, hypotenuse = 14, leg =

Answer 1

1. c^2 = a^2 + b^2
c^2 = (12)^2 + (5)^2
c^2 = 169
c = 13
answer: hypotenuse = 13 units
(( a pythagorean triple ))

2. a^2 = c^2 - b^2
a^2 = (14)^2 - (9)^2
a^2 = 115
a = 10.72
answer: leg = 10.72 units or 11 units

Answer 2

The square of the hypotenuse is the sum of the squares of its legs.

1. 12^2 + 5^2 = 144 + 25 = 169 = 13^2.

2. 14^2 - 9^2 = 196 - 81 = 115

sqrt (115) = 10.7238....

Answer 3

leg=12,leg=5

Answer 4

The square of the hypotenuse is equal to the sum of the suqares of the other two sides. So...
1. 12^2 + 5^2 = 169 The sq. rt. of 169 is 13

2. 9^2 + ? = 14^2
81 + ? = 196
? = 115 The sq. rt. of 115 is about 10.7

Answer 5

1. leg = 12, leg = 5, hypotenuse =
c^2=a^2+b^2

a=12 b= 5 c=?

c=sqrt[(12)^2+5^2]
=sqrt[144+25]
=sqrt of 169
=13



2. leg = 9, hypotenuse = 14, leg =
a=9 b=? c=14

b=sqrt[(14)^2-9^2]
=sqrt[196-81]
=sqrt of 115
=10.72

Answer 6

1)

c² = a² + b²

√c² = √(12)² + (5)²

√c² = √144 + 25

√c² = √169

c = 13

- - - - -

2)

c² - a² = √b²

√(14)² - (9)² = √b²

√196 - 81 = √b²

√115 = √b²

10.72380529 = b

- - - - - - - - - - -s-

Answer 7

just use the formula a^2+b^2=c^2 where a and b are the legs and c is the hypotenuse

Answer 8

This is simple Pythagoras......

1) 12^2 + 5^2 = 169
sqrt 169 = 13

2) 14^2 = 9^2 + X^2

196 = 81 + X^2
115 = X^2
X = 10.72380529

Answer 9

1.) = 9

2.) = 8

Answer 10

to reply to this question you should use SOH CAH TOA..... SOH= SINE equals opposite over HYPOTENUSE CAH= COSINE equals adjoining over HYPOTENUSE TOA= TANGENT equals opposite over adjoining