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Hmm... example... Get the equivalent angle (in degrees) of 4:15 Pm....

Like getting the angle formed by the minute hand and the hour hand...

THANKS!!

2007-02-22 23:46:46 · 4 answers · asked by Here I am 2 in Science & Mathematics Mathematics

hmmm the hour hand moves with the minute hand right?

how can u know the exact angle formed..


Is there a formula??

thanks

2007-02-23 00:02:42 · update #1

4 answers

360/12=30(degrees per hour)

360/60=6(degrees per min)

|no hours(30)- no. of mins(6)| = degrees of the given time

=|4(30)-15(6)|
=|120-90|
=30 degrees

2007-02-22 23:56:14 · answer #1 · answered by jAmPr0tzz 2 · 1 3

If the time is given in hours (h) and minutes (m), then we are t = h + m/60 hours past noon.

The angle of the hour hand relative to 12:00 noon is 360t / 12 or 30t degrees.

The angle of the minute hand relative to noon is 360m / 60 or 6m degrees.

So the angle formed by the two hands is |30t - 6m| degrees. Subtract the result from 360 if it's greater than 180, to get the interior angle.

2007-02-23 07:55:58 · answer #2 · answered by Anonymous · 0 0

15 / 60
= 0.25 (15 min in hours)

[(4 + 0.25) /12] * 360deg
= 127.5deg (angle between hour hand and 12 o'clock)

0.25 * 360deg
= 90 (angle between min hand and 12 o'clock)

127.5deg - 90deg
= 37.5deg (difference)

Substitude the values accordingly to find the angle of other times.

2007-02-23 08:27:55 · answer #3 · answered by math freak 3 · 1 1

Each hour = 30°

4 hours = 120°

15 minutes is 1/4 hour or 15/60

1/4 = 0.25

120° 25'

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2007-02-23 08:28:28 · answer #4 · answered by SAMUEL D 7 · 0 2

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