My little brother asked me for help with his maths homework and I have no idea how to do this question. Any help would be appreciated.
If a father is five times as old as his son, how long ago was the father 34 years old and the son 2 years old.
Thanks
2007-02-22 19:47:41 · 4 answers · asked by Anonymous in Education & Reference ➔ Homework Help
right now the father is 40 and the son is 8. That means that 6 years ago, the father was 34 and the son was 2. The answer is 6 years.
2007-02-22 20:20:10 · answer #1 · answered by robdog9151 2 · 0⤊ 0⤋
F = 5 x
so - let's see what 5x is - needs to be more than 7
since the father is 34 now and 5 x 7 is 35
next to try is 8 x 5 = 40
hmmmmm son 2 + 6 = 8
dad 34 + 6 = 40
solved - next!
2007-02-23 03:53:30 · answer #2 · answered by tomkat1528 5 · 1⤊ 0⤋
6 years ago.
today father is 5x, son is x.
y years ago, father is 34, son is 2 so
5x=34+y and x=2+y
so: 5 (2+y) = 34+y
10+5y = 34+y
4y=24
y=6
2007-02-23 04:14:37 · answer #3 · answered by rooster1981 4 · 1⤊ 0⤋
8 years
F=5S
F-X=34
S-X=2
5S-x=34 (Substituting F=5S)
5S=34+X
S=(34+X)/5
[(34+X)/5] - X=2
32=4X
8=X
2007-02-23 03:57:18 · answer #4 · answered by jus' me 2 · 0⤊ 0⤋