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does anyone know the answer to this. how many atoms are in 7.0 ng of carbon?

2007-02-22 18:57:52 · 4 answers · asked by FotoFan85 3 in Science & Mathematics Physics

4 answers

1 mol of carbon contains 6 x 10^23 atoms
1 mol of carbon = 12 g
12 g of carbon contais 6 x 10^23 atoms
7.0 x 10^-9 g will contain 6 x 10^23 x 7.0 x 10 ^-9 /12
=3.5 x 10^14

2007-02-22 19:04:39 · answer #1 · answered by ziyaad rcc 2 · 0 0

7.0 ng is 7*10^-9g

this corresponds to 7 10^-9/12 moles of carbon

and since a mole = 6.022 10^23 atoms so


number of atoms 7*10^-9 *6.02210^23/12 = 3.51 10^14

2007-02-23 04:56:07 · answer #2 · answered by maussy 7 · 0 0

carbon's atomic weight is 12. That means 12g of Carbon(one mole) has 6.023 x 10^23 atoms (this is a constant called Avagadro's number).

Therefore, 7 ng i.e. 7 x 10^-9 g of Carbon would have 7/12 x 10^14 atoms.. = 5.833 x 10^13 atoms.

2007-02-23 03:04:14 · answer #3 · answered by Kidambi A 3 · 0 0

12 g of Carbon has 6.022* 10 raise to power 23 atoms. So 1g will have 6.022*10 raise to power23 divided by 12 . 1g has 10 raise to power 6 ng. therefore dividing the answer by 6 and multiflying it by 7 is your answer.


I would have given the aswer myself but sorry my calculator is not working.

2007-02-23 03:06:29 · answer #4 · answered by Anonymous · 0 0

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