Velocity graph changed to position vs time graph?

Question

Velocity graph changed to position vs time graph?

Velocity graph changed to position vs time graph?

seconds - velocity
0-0
1-2.5
2-2.5
3-1.25
4-0
5- -1.25
6- -2.5
7- -3.75
8- -3.75
8.5- 0
9- 0
10- 0

Fist number is time 2nd is velocity at time, what would the positions be at the times?

Answer 1

use s = 1/2 (u + v)t
Assume original position = 0.0

seconds - velocity - position
0 - 0 - 0.0
1 - 2.5 - 1.25 (= 1/2(0.0 + 2.5)(1))
2 - 2.5 - 3.75 (= 1.25 + 1/2(2.5 + 2.5)(1))
3 - 1.25 - 5.625 (= 3.75 + 1/2(2.5 + 1.25)(1))
4 - 0 - 6.25 (= 5.625 + 1/2(1.25 + 0)(1))
5 - -1.25 - 5.625 (= 6.25 + 1/2(0 - 1.25)(1))
6 - -2.5 - 3.75(= 5.625 + 1/2(-1.25 - 2.5)(1))
7 - -3.75 - 0.625(= 3.75 + 1/2(-2.5 - 3.75)(1))
8 - -3.75 - -3.125(= 0.625 + 1/2(-3.75 - 3.75)(1))
8.5 - 0 - -4.0625(= -3.125 + 1/2(-3.75 + 0)(0.5))
9 - 0 - -4.0625(=-4.0625 + 1/2(0 + 0)(0.5))
10 - 0 - - 4.0625(=-4.0625 + 1/2(0 + 0)(1))