Is it simply a case of trial and error with a calculator... eg trying 5^2, then 5^3 etc until I get close to 100?
2007-02-22 17:26:05 · 5 answers · asked by Rimi 1 in Science & Mathematics ➔ Mathematics
No.
5^x-100 take log of each side
x log 5=log 100=2 divide both sides by log 5
x=2/log 5=2.861
2007-02-22 17:29:54 · answer #1 · answered by yupchagee 7 · 15⤊ 0⤋
Log 100 Divided by log 5.
2007-02-23 01:30:04 · answer #2 · answered by alwaysmoose 7 · 0⤊ 0⤋
Take the log of both sides.
log(a^x)=xlog(a)
x*log(5)=log(100)
x=log(100)/log(5)=2/.699=2.86
2007-02-23 01:30:21 · answer #3 · answered by Rob M 4 · 0⤊ 0⤋
Use natural logs
ln(5^x) = ln(100)
x*ln(5) = 2*ln(10)
x = 2*ln(10)/ln(5)
2007-02-23 01:36:52 · answer #4 · answered by a_liberal_economist 3 · 0⤊ 0⤋
nope u apply log.
log5^x=log100
as u may know logY^x= xlogY
xlog5=log100
log100=2 and log5=0,7
x=2/0,7
x=2.857
2007-02-23 01:31:31 · answer #5 · answered by Λиδѓεy™ 6 · 1⤊ 0⤋