2007-02-22 17:03:37 · 8 answers · asked by simonthe2nd 1 in Science & Mathematics ➔ Mathematics
it can not be put in form a/ b as fraction
2007-02-22 17:12:16 · answer #1 · answered by emy 3 · 0⤊ 0⤋
User "Maths Rocks" has an excellent answer. A similar proof was shown in a class of mine to prove root 2 irrational.
2007-02-22 17:23:17 · answer #2 · answered by John H 4 · 0⤊ 0⤋
since square root of 3 cannot be expressed as a fraction, it is irrational
2007-02-22 17:28:41 · answer #3 · answered by Krish 5 · 0⤊ 0⤋
the difficulty is your assertion: "If a^2 is a distinctive of four and a is an integer, then a ought to be a mulitple of four." That assertion merely works for high numbers and four isn't top. permit a = 2. of course a^2 = 4 is a distinctive of four yet 2 isn't a distinctive of four.
2016-12-18 09:06:07 · answer #4 · answered by roedel 3 · 0⤊ 0⤋
the square root of 3 is a neverending decimal number,
= about 1.73205....
Therefore, it is irrational
2007-02-22 17:07:18 · answer #5 · answered by Derrick_k 2 · 2⤊ 1⤋
suppose √3 is rational
then it can be expressed as:p/q
( simplest ratio threfore they have no common factors)
√3=p/q
3=p^2/q^2
p^2=3q^2
this negates our first statement that p and q are in their simplest ratio therefore √3 cannot be written in p/q form hence it is irrational
2007-02-22 17:12:29 · answer #6 · answered by Maths Rocks 4 · 6⤊ 0⤋
im thinking 1.5 im guessing 1.5 + 1.5 would be three so its 1
2007-02-22 17:11:23 · answer #7 · answered by anthony 1 · 0⤊ 3⤋
http://mathforum.org/library/drmath/view/52619.html
http://www.grc.nasa.gov/WWW/K-12/Numbers/Math/Mathematical_Thinking/irrationality_of_3.htm
2007-02-22 17:06:34 · answer #8 · answered by Anonymous · 1⤊ 1⤋