arithmic sequence?

Question

it says find the first five terms of each arithmetric sequence described.

a1=41, d=5

and if an=1-5n, what is a10

also confused about finding the indicated term of each arithmetric sequence like this one:
a1= -4, d= -9, n=20

if anyone can show me how to do these step by step i'll be grateful

Answer 1

a1=41
d=5
n=10


use the formula

an=a1+(n-1)d

a10=41+(10-1)5
=41+9(5)
=41+45
=86

----------------------------------------------------------------

a1= -4, d= -9, n=20

use again the formula an=a1+(n-1)d

a20=-4+(20-1)-9
=-4+19(-9)
=-4+(-171)
=-175

Answer 2

If the first term is a1 and the common difference is d,then
the second term is a1+d or a1+(2-1)d
the third term=a1+(3-1)d
the fourth term=a+(4-1)d,and
the nth term=a+(n-1)d
so the first five terms of your problem are
41,41+5,41+2*5 ,41+3*5,41+4*5,or
41,46,51,56,61
# iSecond part of your problem is easy and once you follow the formula it should not trouble you.
Here a= -4,d=-9
Therefore 20th term
= -4+(20-1)*-9
= -4+(19)(-9)
= -4-171
= -175

Answer 3

Use this formula to find a specific term:
a(n)=a(1)+(n-1)d
For the sum of first n terms use
S(n)=n/2[2a(1)+(n-1)d]
where
a1=first term d= difference b/w cosecutive terms
n=term number
an=1-5n--->a10=1-5(10)= -49