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14 answers

let the first no=x
second no.=y

x/y=8(or x=8y)
x+y=72


solve for y
by substituting(use the 2nd equation)

x+y=72
8y+y=72(substitute the value of x in the first equation to the x in the 2nd equation)

~>
9y=72
9y/9=72/9
y=8


then let us solve the value of x using the 2nd equation

x+y=72
x+8(the value of y we got)=72
x=72-8
x=64


and the answer is

1st no.=64
2nd no.=8

2007-02-22 22:24:28 · answer #1 · answered by jAmPr0tzz 2 · 0 0

Let the two numbers be represented by X and Y. Then we have:

(1) X/Y = 8 and (2) X + Y = 72

Rearrange (1) to get X = 8Y

Substitute 8Y for X in (2) to get 8Y + Y = 72. Hence, 9Y = 72, Y Y = 72/9, Y = 8.

Thus X + 8 = 72, X = 72 - 8, X = 64.

Check using (1): X/Y = 64/8 = 8

Answer: the two numbers are 8 and 64

2007-02-23 03:15:40 · answer #2 · answered by RATTY 7 · 0 0

64+8=72

2007-02-23 00:14:26 · answer #3 · answered by frodo 1 · 0 0

quotient of two numbers is 8 so we get

x/y = 8

or x = 8y......(1)

Also,...The sum of the same two numbers is 72. so we get

x + y = 72..(2)....

substitute the value of x from (1) into (2)

8y + y = 72

9y = 72

Divide both sides by 9 and we get ..

y = 8...

now substitute the value of y = 8 in (1)...

we get ...x = 64

if u want to verify the answer put the value of x and y either in (1)or (2)...if LHS = RHS...our answer is correct ..

hope this will help u

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2007-02-23 08:11:08 · answer #4 · answered by ? 1 · 0 0

64 and 8

2007-02-23 09:44:24 · answer #5 · answered by Emilee 5 · 0 0

64 and 8

2007-02-23 00:00:51 · answer #6 · answered by greecevaca 4 · 0 0

Sixty-Four and Eight

64/8 = 8
64 + 8 = 72

2007-02-23 01:31:02 · answer #7 · answered by Tropic-of-Cancer 5 · 0 0

64 and 8 definitely

2007-02-23 06:01:36 · answer #8 · answered by Dan64 2 · 0 0

64 and 8.

64/8=8
64+8=72

2007-02-23 00:04:47 · answer #9 · answered by samspurlin 1 · 0 0

64 & 8

2007-02-23 00:02:25 · answer #10 · answered by BUNGLE!! 5 · 0 0

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