let the first no=x
second no.=y
x/y=8(or x=8y)
x+y=72
solve for y
by substituting(use the 2nd equation)
x+y=72
8y+y=72(substitute the value of x in the first equation to the x in the 2nd equation)
~>
9y=72
9y/9=72/9
y=8
then let us solve the value of x using the 2nd equation
x+y=72
x+8(the value of y we got)=72
x=72-8
x=64
and the answer is
1st no.=64
2nd no.=8
2007-02-22 22:24:28
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answer #1
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answered by jAmPr0tzz 2
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Let the two numbers be represented by X and Y. Then we have:
(1) X/Y = 8 and (2) X + Y = 72
Rearrange (1) to get X = 8Y
Substitute 8Y for X in (2) to get 8Y + Y = 72. Hence, 9Y = 72, Y Y = 72/9, Y = 8.
Thus X + 8 = 72, X = 72 - 8, X = 64.
Check using (1): X/Y = 64/8 = 8
Answer: the two numbers are 8 and 64
2007-02-23 03:15:40
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answer #2
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answered by RATTY 7
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64+8=72
2007-02-23 00:14:26
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answer #3
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answered by frodo 1
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quotient of two numbers is 8 so we get
x/y = 8
or x = 8y......(1)
Also,...The sum of the same two numbers is 72. so we get
x + y = 72..(2)....
substitute the value of x from (1) into (2)
8y + y = 72
9y = 72
Divide both sides by 9 and we get ..
y = 8...
now substitute the value of y = 8 in (1)...
we get ...x = 64
if u want to verify the answer put the value of x and y either in (1)or (2)...if LHS = RHS...our answer is correct ..
hope this will help u
For further quries please feel free to contact at :-
www.tooldirect.co.uk/ikdeep/
2007-02-23 08:11:08
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answer #4
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answered by ? 1
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64 and 8
2007-02-23 09:44:24
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answer #5
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answered by Emilee 5
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64 and 8
2007-02-23 00:00:51
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answer #6
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answered by greecevaca 4
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Sixty-Four and Eight
64/8 = 8
64 + 8 = 72
2007-02-23 01:31:02
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answer #7
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answered by Tropic-of-Cancer 5
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64 and 8 definitely
2007-02-23 06:01:36
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answer #8
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answered by Dan64 2
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64 and 8.
64/8=8
64+8=72
2007-02-23 00:04:47
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answer #9
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answered by samspurlin 1
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64 & 8
2007-02-23 00:02:25
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answer #10
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answered by BUNGLE!! 5
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