with a length of 7.64 m and a negligible mass. Starting from the ends of the pole, the skaters pull themselves along the pole until they meet. How far will the 52.0 kg skater move?
2007-02-22 15:45:40 · 3 answers · asked by m n 1 in Science & Mathematics ➔ Physics
The center of mass of the skaters will be stationary if there is no friction.
2007-02-22 18:15:36 · answer #1 · answered by meg 7 · 0⤊ 1⤋
permit their a lot be A kg (for Al) and J kg (for Jo). A + J = 168------------------------- (a million) initially at relax, so preliminary momentum = 0 very final momentum = A (0.80 5) + J (-a million.4), via fact that opposite path. using thought of conservation of Momentum, 0.85A - a million.4J = 0 0.85A = a million.4J J = (0.85A / a million.4) ----------------------(2) Sub (2) into (a million), A + (0.85A / a million.4) = 168 appearing some algebra, 2.25A = 235.2 A = 104.5 kg (ans)
2016-11-25 01:16:03 · answer #2 · answered by ? 4 · 0⤊ 0⤋
non-solvable. It depends on the individul rates of pulling .
2007-02-22 15:56:59 · answer #3 · answered by Anopheles 1 · 0⤊ 0⤋