I Need Serious help with this one Calculus problem....?

Question

PLEASE help me with this as SOON as possible:

find the integral of
x2-x+1/√x dx

sorry...i didn't specify that the quadratic is all divided by the square root x !!!!

Answer 1

I assume that the original expression was
(x2-x+1/√x) dx
integral of x2 dx is 1/3x^3 + C1
integral of -x dx is -1/2x^2 +C2
integral of 1/√x=x^(-1/2) is -2x^(1/2)+C3=-2√x+ C3
the combined integral is
1/3x^3 -1/2x^2 -2√x +C

Answer 2

You just take the antiderivative of (x^2-x+1/√x)dx, which would be
(1/3)x^3-(1/2)x^2+2√x+C
where C is any constant