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a) CHCl=CHCl


b) CH2=CH-CHCl2


c) ClBrCHCl


d) (CH3)2C=CH-CH3


e) 1,1-dichloroethene

2007-02-22 15:11:55 · 5 answers · asked by JD 1 in Science & Mathematics Chemistry

5 answers

Draw structure and see if switching positions would make a difference. You are allowed to flip a compound.
a. Has isomers
b. Doesnt have isomers
c. Usually not considered in terms of cis and trans. There are isomers though
d. Doesnt have isomers. Variant on (b)
e. No isomers.

2007-02-22 15:20:02 · answer #1 · answered by cattbarf 7 · 0 0

Dude it helps to draw the molecules out on paper, then it makes sense.

2007-02-22 23:20:58 · answer #2 · answered by Veronica Almighty 2 · 0 0

a and c.

They have two different groups on both sides of the double bonded carbons.

2007-02-22 23:21:29 · answer #3 · answered by novangelis 7 · 0 0

a,c,e..are having isomers butnt b,d bcoz they have similar grops binding to carbon on one side

2007-02-23 04:36:50 · answer #4 · answered by Anonymous · 0 0

a, b(not sure) and d and e.

2007-02-22 23:21:09 · answer #5 · answered by Ieshwar 2 · 0 0

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