Electric field?

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The difference in potential between the accelerating plates of a TV set is about 23 kV. The distance between these plates is 1.4 cm.
Find the magnitude ofthe uniform electric field in this region

2007-02-22 14:58:44 · 2 answers · asked by the poo goo 2 in Science & Mathematics ➔ Physics

2 answers

Easy E = V/d = 23000/.014m

2007-02-22 15:07:44 · answer #1 · answered by hello 6 · 0⤊ 0⤋

The electric fieild is the negative gradient of the potential, so the units are in Volts per meter. Just divide 23e3 V by 0.014 m to get the answer in (V/m)

2007-02-22 15:14:53 · answer #2 · answered by Jess 2 · 0⤊ 0⤋